Greetings my fellow watercoolers,
I set up my 2nd watercooled case about 6-7 months ago and have had no problems with heat/leakage/etc. The only parts I've been cooling is my GPU and CPU.
This christmas, Santa gave me a second Tyee waterblock (for X1900 cards) in crossfire configuration for my second video card but he forgot new tubes! What's worst is that the supplier I got my tubes from no longer sells them!
I still have about 6-7 feet of unused Clearflex tubing from my last installation, the rest is in use right now and has been for half a year now.
Question: Once I drain out my system, can the used tubing be re-used? The two main concerns of mine is a) the blue UV dye might have penetrated the tubing and stained it blue (I'm changing coolant to red) and b) the ends of the tubes might be stretched out from the barbs and will be a loose fit when I connect them to new (but same-size) barbs.
Other than that is there any problem?
Is there a good way to clean out the tubes?
Is it true that the internet is a series of tubes? >.>
kthx
I set up my 2nd watercooled case about 6-7 months ago and have had no problems with heat/leakage/etc. The only parts I've been cooling is my GPU and CPU.
This christmas, Santa gave me a second Tyee waterblock (for X1900 cards) in crossfire configuration for my second video card but he forgot new tubes! What's worst is that the supplier I got my tubes from no longer sells them!
I still have about 6-7 feet of unused Clearflex tubing from my last installation, the rest is in use right now and has been for half a year now.
Question: Once I drain out my system, can the used tubing be re-used? The two main concerns of mine is a) the blue UV dye might have penetrated the tubing and stained it blue (I'm changing coolant to red) and b) the ends of the tubes might be stretched out from the barbs and will be a loose fit when I connect them to new (but same-size) barbs.
Other than that is there any problem?
Is there a good way to clean out the tubes?
Is it true that the internet is a series of tubes? >.>
kthx